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Ã· 11 â 13.909 â no - Esdistancia

📅 March 17, 2026 👤 scraface

Mar 17, 2026

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To $(1,1,0)$: $\sqrt{1 + 0 + 1} = \sqrt{2}$
To $(1,0,1)$: $\sqrt{1 + 1 + 0} = \sqrt{2}$
All distances match.
Thus, the fourth vertex is $\boxed{(0,1,1)}$.
Question: Find all angles $z \in [0^\circ, 360^\circ]$ that satisfy
2\sin^2 z - 3\sin z + 1 = 0
Let $x = \sin z$. Then:
2x^2 - 3x + 1 = 0
Solve the quadratic:
x = \frac{3 \pm \sqrt{9 - 8}}{4} = \frac{3 \pm 1}{4} \Rightarrow x = 1...

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