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Home » \[ 11 = 7\theta \] - Esdistancia

\[ 11 = 7\theta \] - Esdistancia

📅 March 17, 2026 👤 scraface

Mar 17, 2026

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📌 \( \frac{8}{3} \), \( (\frac{8}{3})^2 = \frac{64}{9} \), \( (\frac{8}{3})^3 = \frac{512}{27} \)

📌 Jede Term:

📌 \( (z + \frac{8}{3})^3 = z^3 + 3\cdot\frac{8}{3}z^2 + 3\cdot\frac{64}{9}z + \frac{512}{27} = z^3 + 8z^2 + \frac{192}{9}z + \frac{512}{27} = z^3 + 8z^2 + \frac{64}{3}z + \frac{512}{27} \)

📌 \( -8(z + \frac{8}{3})^2 = -8(z^2 + \frac{16}{3}z + \frac{64}{9}) = -8z^2 - \frac{128}{3}z - \frac{512}{9} \)

📌 \( 9(z + \frac{8}{3}) = 9z + 24 \)

📌 z^3 + 8z^2 + \frac{64}{3}z + \frac{512}{27} -8z^2 - \frac{128}{3}z - \frac{512}{9} + 9z + 24 - 18

📌 = z^3 + \left(8 - 8\right)z^2 + \left(\frac{64 - 128 + 27}{3}\right)z + \left(\frac{512}{27} - \frac{1536}{27} + \frac{648}{27} - \frac{486}{27}\right)

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