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📅 March 17, 2026 👤 scraface

Mar 17, 2026

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نحن بحاجة إلى أن تكون المسافات من $D$ إلى $A$ و $B$ و $C$ جميعها تساوي...
\sqrt{x^2 + y^2 + z^2} = a\sqrt{2} \quad \Rightarrow \quad x^2 + y^2 +...
بعد ذلك، المسافة من $D$ إلى $B$:
\sqrt{(x-a)^2 + (y-a)^2 + z^2} = a\sqrt{2} \quad \Rightarrow \quad (x-...
بتوسيع وتعويض $x^2 + y^2 + z^2 = 2a^2$:
x^2 - 2ax + a^2 + y^2 - 2ay + a^2 + z^2 = 2a^2 \quad \Rightarrow \quad...
أخيرًا، المسافة من $D$ إلى $C$:
\sqrt{x^2 + (y-a)^2 + (z-a)^2} = a\sqrt{2} \quad \Rightarrow \quad x^2...
x^2 + y^2 - 2ay + a^2 + z^2 - 2az + a^2 = 2a^2 \quad \Rightarrow \quad...
x + y = a \quad \text{و} \quad y + z = a

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