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\boxed\langle 1, 0, 4 \rangle - Esdistancia

📅 March 17, 2026 👤 scraface

Mar 17, 2026

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We solve the system from:
\( a + b + c + d = 4 \)
\( 8a + 4b + 2c + d = 15 \)
\( 27a + 9b + 3c + d = 40 \)
\( 64a + 16b + 4c + d = 85 \)
Subtract (1) from (2):
\[ (8a + 4b + 2c + d) - (a + b + c + d) = 15 - 4 \]
\[ 7a + 3b + c = 11 \quad \text{(E1)} \]
Subtract (2) from (3):

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