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Home » But earlier quadratic: discriminant正确. - Esdistancia

But earlier quadratic: discriminant正确. - Esdistancia

📅 March 17, 2026 👤 scraface

Mar 17, 2026

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\[ \frac{k(1 - t^2)}{(t^2 + 1)^2} = 0 \]
The numerator must be zero:
\[ 1 - t^2 = 0 \]
\[ t^2 = 1 \]
\[ t = \pm 1 \]
Check the second derivative or evaluate \(C(t)\) at critical points an...
\[ C(1) = \frac{k \cdot 1}{1^2 + 1} = \frac{k}{2} \]
\[ C(-1) = \frac{k \cdot (-1)}{(-1)^2 + 1} = \frac{-k}{2} \]
Since \(C(t) \to 0\) as \(t \to \pm \infty\), the maximum occurs at \(...
\(\boxed{t = 1}\)

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