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\equiv 4 \pmod10 - Esdistancia

📅 March 17, 2026 👤 scraface

Mar 17, 2026

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We start with the identity for the square of a sum:
Rearranging gives:
a^2 + b^2 = (a + b)^2 - 2ab
Substitute the given values \( a + b = 4 + 2i \) and \( ab = 5 + 3i \)...
a^2 + b^2 = (4 + 2i)^2 - 2(5 + 3i)
First, compute \( (4 + 2i)^2 \):
Now compute \( 2(5 + 3i) = 10 + 6i \).
a^2 + b^2 = (12 + 16i) - (10 + 6i) = 2 + 10i
\boxed{2 + 10i}
For all real numbers \( x \) and \( y \), find the number of functions...

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