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Home » R(-2) = -2 - 1 = -3 - Esdistancia

R(-2) = -2 - 1 = -3 - Esdistancia

📅 March 17, 2026 👤 scraface

Mar 17, 2026

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Now, intersections:
\(A \cap B\) = no I and no F → all M: only 1 configuration,
Similarly, \(A \cap C = 1\), \(B \cap C = 1\),
\(A \cap B \cap C = 0\) (impossible to have no types).
By inclusion-exclusion, the number of invalid configurations (missing...
|A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |A \cap C| - |B \ca...
= 3 \cdot 512 - 3 \cdot 1 + 0 = 1536 - 3 = 1533
Thus, valid configurations with all three types present:
3^9 - 1533 = 19683 - 1533 = 18150
Therefore, the number of valid configurations is \(\boxed{18150}\).

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