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Home » Thus, the value of $ ab $ is $\boxed12$. - Esdistancia

Thus, the value of $ ab $ is $\boxed12$. - Esdistancia

📅 March 17, 2026 👤 scraface

Mar 17, 2026

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h(2) = 8a + 2p + q = 10 \quad ext{(2)}
h(3) = 27a + 3p + q = 24 \quad ext{(3)}
Now subtract (a) from (b):
Plug into (a):
7\left(rac{2}{3}
ight) + p = 6 \Rightarrow rac{14}{3} + p = 6 \Rightarrow p = 6 - rac...
Now from (1):
rac{2}{3} + rac{4}{3} + q = 4 \Rightarrow rac{6}{3} + q = 4 \Rightar...
Thus \( h(x) = rac{2}{3}x^3 + rac{4}{3}x + 2 \)
Now compute \( h(0) = 0 + 0 + 2 = 2 \)

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