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Home » x^3 - 8 = (x - 2)(x^2 + 2x + 4) - Esdistancia

x^3 - 8 = (x - 2)(x^2 + 2x + 4) - Esdistancia

📅 March 17, 2026 👤 scraface

Mar 17, 2026

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First compute \( lpha^2 \):
lpha = 1 + i \Rightarrow lpha^2 = (1+i)^2 = 1 + 2i + i^2 = 1 + 2i -...
lpha^4 = (lpha^2)^2 = (2i)^2 = 4i^2 = -4
lpha^4 + 3 = -4 + 3 = -1 = a(1+i) + b = a + ai + b
Equating real and imaginary parts:
Real: \( a + b = -1 \)
Imaginary: \( a = 0 \)
Wait â imaginary part gives \( a = 0 \)? But then from real: \( b =...
Now try \( u = eta = 1 - i \):
eta^2 = (1 - i)^2 = 1 - 2i + i^2 = 1 - 2i - 1 = -2i

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